Tasks: Data types, variables and constants

126 thoughts on “Tasks: Data types, variables and constants”

1. Thank you for the opportunity to practice.
   It really helps in the realization of the material!

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   1. Rada, that you've found useful information for you on our website! stay with us!

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      1. In the second assignment error, The second variable is not equal to the first increase in three, and it is issued on the same with the following expression…

2. ahahahah :D
   I am currently in a second complicated zadachu.I wrote instead 15 lines – 30 :D
   little protupila,but overall I left everything well.

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3. everything is good but not enough, I want more tasks and with the ever-increasing level of complexity! :)

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4. I enrolled in the second problem a little differently, regarding display, and in general all the same
   #include

   using namespace std;

   int main (int x, int y, int z)

   {
x = 15;
y = x * 3;
z = x + y;

   cout << x << "\n" << y << "\n"<< z << "\n";

   system("pause");
return 0;
}

   Reply

5. and the third reason I also thought, you must itself determine the number of devices, and this turned out at me like this
   #include
#include

   using namespace std;
int total;

   void totalfunc();
int main ()

   {
setlocale(LC_CTYPE, "rus");
totalfunc();
system("pause");
return 0;
}

   void totalfunc()
{
int cups, spoon, saucer;

   cout < < cups; cout << spoon; cout << saucer; total = cups + spoon + saucer; cout << "Сумма предметов на столе равна: "; cout << total; }

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6. The decision on the first task. What are the good and bad side is, in my decision. newcomer,severely beat. (Rows not Russian because he wrote in Dev`e,not at home).

   #include
#include

   using std::cout;
using std::cin;
using std::endl;

   int choko=0;
int coffee=0;
int milk=0;
int tov=0;
float sumch=0;
float sumcof=0;
float summilk=0;
float sttov=0;

   int tovari();
float stoimost();
float summa();

   int main()
{
tovari();
stoimost();
summa();

   system("PAUSE");
return 0;
}

   int tovari()
{
cout<<"--------------------------------------------"<<"\n";

   cout<<"Vvedite kol-vo kuplennix productov \n";
cout<<"--------------------------------------------"<<"\n";

   cout<<choko;
cout<<coffee;
cout<<milk;

   tov=choko+coffee+milk;

   cout<<"--------------------------------------------"<<"\n";
cout<<"Obshee kol-vo kuplennix tovarov= "<<tov<<"\n";
cout<<"--------------------------------------------"<<"\n";

   return 0;
}

   float stoimost()
{
cout<<"--------------------------------------------"<<"\n";

   cout<<"Vvedite stoimost kuplennix productov \n";
cout<<"--------------------------------------------"<<"\n";

   cout<<sumch;
cout<<sumcof;
cout<<summilk;

   return 0;
}

   float summa()
{
cout<<"--------------------------------------------"<<"\n";
cout<<"Stoimost pokupok \n";
cout<<"--------------------------------------------"<<"\n";

   cout<<"--------------------------------------------"<<"\n";
sumch*=choko;
cout<<"Stoimost plitok shokolada= "<<sumch<<"\n";
sumcof*=coffee;
cout<<"Stoimost banok cofe= "<<sumcof<<"\n";
summilk*=milk;
cout<<"Stoimost paketov moloka= "<<summilk<<"\n";
cout<<"--------------------------------------------"<<"\n";
sttov=sumch+sumcof+summilk;
cout<<"Obshya summa k oplate= "<<sttov<<"\n";
cout<<"--------------------------------------------"<<"\n";

   return 0;
}

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   1. As the dofiga code and really useless.

      using namespace std;

      int main() {

      int milk, chocolate, coffe;
float milkcost = 10.1;
float chocolatecost = 11.85;
float coffecost = 15.4;
cout << milk;
cout << chocolate;
cout << coffe;
cout << "You buy " << milk << " botles of milk " << milkcost << " * " << milk << " = " << (milk * milkcost) << endl;
cout << "You buy " << chocolate << " chocolates " << chocolatecost << " * " << chocolate << (chocolate * chocolatecost) << endl;
cout << "You buy " << coffe << " coffe's " << coffecost << " * " << coffe << (coffe * coffecost) << endl;
cout << "Total: " << (milk * milkcost) + (chocolate * chocolatecost) + (coffe * coffecost)
return 0;
system ("pause");
};

      Reply

7. Formulation of the task:
   Write program calculating circuit resistance elektriche¬skoy, consisting of two parallel-connected resistors. The recommended screen view during execution of the program (data, user Submitted, bolded).
   Calculation of the electrical circuit in parallel connection of resistance elements.
   Enter the raw data:
   The magnitude of the first resistance (ohm) -> 15
   The magnitude of the second resistance (ohm)-> 20
   circuit resistance: 8.57 ohm
   Developing solutions algorithm.

   chart

   Defining the program

   L - value of the first resistance (ohm), a float variable
   G - a second resistance value (ohm), a float variable
   R - resistance of the circuit (ohm), a float variable

   The full text of the program
   //---------------------------------------------------------------------------

   #include
#include
void main ()

   {
float L, G, R;
printf("velichina pervogo soprotivlenia (Om) : ") ;
scanf("%f", &L) ;
printf("velichina vtorogo soprotivlenia (Om) : ") ;
scanf("%f", &G) ;
R=L*G/(L+G);
printf("\n soprotivlenie cepi %f Om",R);
scanf("%f", &L);
}
//---------------------------------------------------------------------------

   The results of the work program
   When the program on the screen, such results have been removed:

   The magnitude of the first resistance: 15
   The magnitude of the second resistance 20
   circuit resistance 8,57

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8. The first line of the input file are two integers a and b (-109 ≤ a, b ≤ 109). Your program needs to display a single number - the result of the expression a – b.

   Input data:
   Two integers a and b (-109 ≤ a,b ≤ 109).

   Output:
   the result of the expression a – b.

   Reply