Tasks: arithmetic operations in C ++

If you have already read the articleArithmetic operations in C ++ you can begin to practice.

1. Common task: Given the four-digit number (for example 5678), display the numbers in reverse order of which is the number of member. That is, we should see on the screen 8765. Tip: to take from among the individual numbers, should be applied to the modulo 10.

Show code

[crayon-69ed5b877c149778002172/]
Result:

2. The site of almost any commercial bank, you can find the so-called Deposit calculator, which allows people to, not wishing to go into the formula for calculating interest rates, to know how much they will receive. To do this, they just fill in certain fields, press the button and see the result. This is a simple program, which has already been able to write each one of you. So, a task: The user enters the amount of the deposit and the number of months of keeping money in the bank. It is necessary to calculate and show the screen profit from the deposit in a month, for the entire term of the deposit, and the total amount payable at the end of the period. Currency let it be – U.S. dollar. Interest rate – 5% APR. The formula for calculating percent per month– SumDeposit * (interest rate / 100) / daysperyear * dayspermonths.

Show code

#include <iostream>
using namespace std;

int main()
{
setlocale(LC_ALL, "rus");

float sumDeposit = 0; // сумма депозита
int amountMonth = 0; // количество месяцев
float profit = 0; // прибыль
float annualRate = 5; // пять процентов годовых
int daysInYear = 365;
int daysInMonth = 30;

cout << "Введите сумму депозита в долларах: ";
	cin >> sumDeposit;
cout << "Введите количество месяцев: ";
	cin >> amountMonth;

cout << "\nРасчет\n";
cout << "=======================================\n";
cout << "Проценты в месяц: ";
// проводим расчет по формуле и записываем в переменную profit
profit = sumDeposit * (annualRate / 100)  / daysInYear * daysInMonth;

cout << sumDeposit << " * " << annualRate << "%  / " << daysInYear
	 << " * " << daysInMonth << " = " << profit << " $" << endl;

cout << "Проценты за весь срок: ";
// умножаем % за 1 месяц на весь срок депозита и записываем в profit
profit *= amountMonth;
cout << profit << " $"  << endl;

cout << "Общая сумма выплаты в конце срока: "
	 << sumDeposit + profit  << " $";
cout << endl << endl;

return 0;
}

#include <iostream>

using namespace std;

int main()

{

setlocale(LC_ALL, "rus");

float sumDeposit = 0; // сумма депозита

int amountMonth = 0; // количество месяцев

float profit = 0; // прибыль

float annualRate = 5; // пять процентов годовых

int daysInYear = 365;

int daysInMonth = 30;

cout << "Введите сумму депозита в долларах: ";

cin >> sumDeposit;

cout << "Введите количество месяцев: ";

cin >> amountMonth;

cout << "\nРасчет\n";

cout << "=======================================\n";

cout << "Проценты в месяц: ";

// проводим расчет по формуле и записываем в переменную profit

profit = sumDeposit * (annualRate / 100) / daysInYear * daysInMonth;

cout << sumDeposit << " * " << annualRate << "% / " << daysInYear

<< " * " << daysInMonth << " = " << profit << " $" << endl;

cout << "Проценты за весь срок: ";

// умножаем % за 1 месяц на весь срок депозита и записываем в profit

profit *= amountMonth;

cout << profit << " $" << endl;

cout << "Общая сумма выплаты в конце срока: "

<< sumDeposit + profit << " $";

cout << endl << endl;

return 0;

}

Result:

[crayon-69ed5b877c156045476012/]

Result:

Perhaps you have any questions about the solution of tasks – ask them in the comments!

156 thoughts on “Tasks: arithmetic operations in C ++”


#include 
using namespace std;

int getNumber()
{
	int a;
	cout <> a;

	while (true)
	{
		if (cin.fail() || a  9999)
		{
			cin.clear();
			cin.ignore(32767, '\n');
			cout << "Ошибка ввода, повторите попытку" << endl;
			cout << "===============================" << endl;
			cout <> a;
		}
		else
		{
			cin.ignore(32767, '\n');
			return a;
		}
	}
}

int main()
{
	setlocale(LC_ALL, "ru");

	int mainNumber = getNumber();

	int a = mainNumber;

	int b = (a % 10)*1000;// 1 цифра нового числа

	a /= 10;
	int c = (a % 10) * 100; // 2я цифра нового числа

	a /= 10;
	int d = (a % 10) * 10;//  3я цифра нового числа

	
	a /= 10;
	int e = a % 10 ;// последняя циффра нового числа
	

	int newNumber = b + d + c + e; 

	cout << endl;
	if (newNumber == mainNumber) cout << newNumber << " - это полиндром" << endl;
	else cout << newNumber << " - НЕ полиндром" << endl;
}

#include

using namespace std;

int getNumber()

{

int a;

cout <> a;

while (true)

{

if (cin.fail() || a 9999)

{

cin.clear();

cin.ignore(32767, '\n');

cout << "Ошибка ввода, повторите попытку" << endl;

cout << "===============================" << endl;

cout <> a;

}

else

{

cin.ignore(32767, '\n');

return a;

}

int main()

{

setlocale(LC_ALL, "ru");

int mainNumber = getNumber();

int a = mainNumber;

int b = (a % 10)*1000;// 1 цифра нового числа

a /= 10;

int c = (a % 10) * 100; // 2я цифра нового числа

a /= 10;

int d = (a % 10) * 10;// 3я цифра нового числа

a /= 10;

int e = a % 10 ;// последняя циффра нового числа

int newNumber = b + d + c + e;

cout << endl;

if (newNumber == mainNumber) cout << newNumber << " - это полиндром" << endl;

else cout << newNumber << " - НЕ полиндром" << endl;

}

#include <iostream>
using namespace std;

int getNumber()
{
	int a;
	cout << "Введите целое положительное четырехзначное число: ";
	cin >> a;

	while (true)
	{
		if (cin.fail() || a < 1000 || a > 9999)
		{
			cin.clear();
			cin.ignore(32767, '\n');
			cout << "Ошибка ввода, повторите попытку" << endl;
			cout << "===============================" << endl;
			cout << "Введите целое положительное четырехзначное число: ";
			cin >> a;
		}
		else
		{
			cin.ignore(32767, '\n');
			return a;
		}
	}
}

int main()
{
	setlocale(LC_ALL, "ru");

	int mainNumber = getNumber();

	int a = mainNumber;

	int b = (a % 10)*1000;// 1 цифра нового числа

	a /= 10;
	int c = (a % 10) * 100; // 2я цифра нового числа

	a /= 10;
	int d = (a % 10) * 10;//  3я цифра нового числа

	
	a /= 10;
	int e = a % 10 ;// последняя циффра нового числа
	

	int newNumber = b + d + c + e; 

	cout << endl;
	if (newNumber == mainNumber) cout << newNumber << " - это полиндром" << endl;
	else cout << newNumber << " - НЕ полиндром" << endl;
}

#include <iostream>

using namespace std;

int getNumber()

{

int a;

cout << "Введите целое положительное четырехзначное число: ";

cin >> a;

while (true)

{

if (cin.fail() || a < 1000 || a > 9999)

{

cin.clear();

cin.ignore(32767, '\n');

cout << "Ошибка ввода, повторите попытку" << endl;

cout << "===============================" << endl;

cout << "Введите целое положительное четырехзначное число: ";

cin >> a;

}

else

{

cin.ignore(32767, '\n');

return a;

}

int main()

{

setlocale(LC_ALL, "ru");

int mainNumber = getNumber();

int a = mainNumber;

int b = (a % 10)*1000;// 1 цифра нового числа

a /= 10;

int c = (a % 10) * 100; // 2я цифра нового числа

a /= 10;

int d = (a % 10) * 10;// 3я цифра нового числа

a /= 10;

int e = a % 10 ;// последняя циффра нового числа

int newNumber = b + d + c + e;

cout << endl;

if (newNumber == mainNumber) cout << newNumber << " - это полиндром" << endl;

else cout << newNumber << " - НЕ полиндром" << endl;

}

Madiyar says:
18.01.2021 at 12:09
#include
using namespace std;
int main(){
unsigned long int a,c=0;
cin>>a;
while (a!=0){
c*=10;
c=c+a;
a/=10;
}
cout<<c;
return 0;
}
Reply
1. Madiyar says:
  18.01.2021 at 12:12
  Checking for palindrome .
  You don't have to write Unsigned long.
  Reply
ArtLexa says:
29.03.2021 at 10:41
#include
using namespace std;
int main()
{
setlocale(LC_CTYPE, “Russian”);
float deposit = 0, srok = 0;
cout <> deposit;
cout <> srok;
cout << "прибыль в месяц:" << deposit * 0.05 / 365 * 30 << "$" << endl;
cout << "прибыль за весь срок:" << deposit * 0.05 / 365 * 30 * srok << "$" << endl;
cout << "итоговая выплата:" << deposit * 0.05 / 365 * 30 * srok + deposit << "$" << endl;
return 0;
}
Reply
Light Skorkina says:
17.07.2021 at 08:48
I'll go against the rules. Why write big code?, if possible so:
#include
using namespace std;
int main()
{
char a, b, c, d;
cin >> a >> b >> c >> d;
cout << d << c << b << a;
}
Reply
1. Ruslan Kisanov says:
  14.07.2022 at 21:26
  Ahahahaahhaahah brilliant.
  I modified your code a little.
  #include
  using namespace std;
  int main ()
  {
  int a=5;
  int b=6;
  int c=7;
  int d=8;
  cout << "Данно целое число: " < <a << b << c << d << endl;
  cout << "Число наизнанку: " << d << c << b << a << endl;
  }
  Reply
O__O says:
20.07.2021 at 07:38
#include
using namespace std;
void magazine() { //zadacha iz purecodecpp.com/archives/433
int m = 0, sh = 0, co = 0;
int sum;
int mRub = 79, shRub = 124, coRub = 735;
int sumRub;
int menunum;
system(“color 2″);
for (menunum = 0; grow < 4;) {
cout << "\t\t~ DOBRO POJALOVAT' V MAGAZIN CITY 17 ~\n\n";
cout <> DOBAVIT’ V KORZINU: \n====================================================================\n”;
cout <> 1. MOLOKO\t\t\t79 rub.\t\t—-\t” << m << "\tsht.\n";
cout <> 2. SHOKOLADKA\t\t124 rub.\t—-\t” << sh << "\tsht.\n";
cout <> 3. DEVYATOK YAITS\t\t735 rub.\t—-\t” << co << "\tsht.\n";
cout <> 4. BUY’ S DOSTAVKOY\t3500 rub.\t—-\t-\t—-\n>>\n>> “;
cin >> grow;
switch (grow) {
case 1:
m++;
break;
case 2:
sh++;
break;
case 3:
co++;
break;
case 4:
sum = m + sh + co;
mRub *= m;
shRub *= sh;
coRub *= co;
sumRub = mRub + shRub + coRub + 3500;
cout << "\n====================================================================\n";
cout <> ITOGO:\t\t\t” << sumRub << "* rub.\t—-\t" << sum <> *s uchetom deliveries :)\n\n”;
system(“pause”);
default:
menunum = 0;
}
if (grow != 4) {
menunum = 0;
}
system(“cls”);
}
}
void bank() { //zadacha iz purecodecpp.com/archives/433
int depo = 0, mes = 0, prib = 0;
int procmes = 0, procgod = 0;
int menunum;
system(“color 2″);
for (menunum = 0; grow < 3;) {
cout << "\t\t~ DOBRO POJALOVAT' V BANK CITY 17 ~\n\n";
cout <> DEPOZITNIY KALKULATOR: \n============SPESHITE! PROTSENTNAYA STAVKA 0.2% THE GODS!!!========\n>>\n”;
cout <> 1. SUMMA DEPOZITA\t\t\t” << depo << "\trub.\n";
cout <> 2. SKOL’KO MESYATSEV HRANIT’\t\t” << my << "\tmesyatsev\n";
cout <> 3. POSCHITAT’ APPROACH…\n>>\n>> “;
cin >> grow;
switch (grow) {
case 1:
system(“cls”);
cout << "\t\t~ DOBRO POJALOVAT' V BANK CITY 17 ~\n\n";
cout <> DEPOZITNIY KALKULATOR: \n============SPESHITE! PROTSENTNAYA STAVKA 0.2% THE GODS!!!========\n>>\n”;
cout <> depo;
break;
case 2:
system(“cls”);
cout << "\t\t~ DOBRO POJALOVAT' V BANK CITY 17 ~\n\n";
cout <> DEPOZITNIY KALKULATOR: \n============SPESHITE! PROTSENTNAYA STAVKA 0.2% THE GODS!!!========\n>>\n”;
cout <> my;
break;
case 3:
procmes = depo * (0.2 / 100) / 365 * 30;
procgod = procmes * 12;
cout << "\n====================================================================\n";
cout <> APPROX’ SOSTAVIT:\n>>\n”;
cout <> V MESYATS:\t\t\t” << procmes << "\trub.\n";
cout <> V GOD:\t\t\t” << procgod << "\trub.\n\n";
system("PAUSE");
default:
menunum = 0;
}
if (grow != 3) {
menunum = 0;
}
system("cls");
}
}
int main()
{
int menuitem = 0;
system("color 2");
cout << "\t\t~ DOBRO POJALOVAT' V 'My HeLLo WORLD!' ~\n\n";
cout <> rousing’ POINT: \n====================================================================\n”;
cout <> 1. MAGAZIN\n”;
cout <> 2. BANK\n”;
cout <> 99. VIHOD\n>>\n>> “;
cin >> small;
switch (small) {
case 1:
system(“cls”);
store();
break;
case 2:
system(“cls”);
bank();
break;
case 99:
system(“exit”);
default:
minuet = 0;
}
return 0;
}
Reply
28 blows says:
20.07.2021 at 12:44
#include
using namespace std;
int main()
{
int num;
cin >> on one;
for (on one; on one != 0; num /= 10)
cout << on one % 10;
return 0;
}
Reply
Novel says:
29.10.2021 at 20:31
I consulted with an economist on the formula for calculating interest, here the program calculates compound interest.
#include
#include
using namespace std;
int main() {
double b, d, x, t, c;
int a;
cout << "enter summ depozit " <> x;
cout << "enter kol-vo mounse " <> a;
cout << "enter % stavku " <> c;
c /= 100;
t = 1 + c / 12;
b = pow(t, a) ;
b *= x;
d = (b – x) / a;
cout << "summa vklada itog : " << b << endl;
cout << "zarabotok v mes : " << d << endl;
return 0;
}
Reply
Alexey says:
31.03.2022 at 06:50
short a=0;
cin >> a;
cout << a % 10;
cout << (a / 10) % 10;
cout << (a / 100) % 10;
cout << (a / 1000) % 10;
Reply

Tasks: arithmetic operations in C ++

156 thoughts on “Tasks: arithmetic operations in C ++”

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