Tasks and solution. С

128 thoughts on “Tasks and solution. С ”

1. Create a program for calculating the specified value
   Y=2f(x)(asinx+of^-(x+3)), where x={-3from
   Z^2
   FROM>0
   FROM<=0

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2. You mixed up the topics.
   You have a topic Two-dimensional arrays go before arrays
   8. Two-dimensional arrays C ++
   9. Arrays in C++
   correct, it's a complete creep, what to first learn a two-dimensional array, and then you tell, WHAT IS AN ARRAY

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3. Compose a program using two-dimensional dynamic arrays to solve the problem according to the variant of an individual task

   Perform a cyclic shift of the elements of a square matrix of dimension × N to the right by k elements in this way: elements of the 1st row are shifted to the last column from top to bottom, out of him – last line from right to left, from her – in the first column from bottom to top, out of him – to the first line; for other elements – likewise.

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4. Write a program, which outputs the value of the expression with respect to three natural variables a, b, c in full
   a(b+c)
   Sample Input:
   3 4 5
   Sample Output:
   3(4+5)=27
   #include
   using namespace std;
   int main()
   {
   int a(3), b(4), c(5);
   cin>>a>>b>>c;
   cout<<"3(4+5)=27";
   return 0;
   }

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   1. #include

      using namespace std;

      int main()
      {
      setlocale (LC_ALL, “Russian”);
      int a, b, c, sum;
      cout << "Введите число a" <> a;
      cout << "Введит число b" <> b;
      cout << "Введите число c" <> c;
      sum = a * (b + c);
      cout << a << " * (" << b << " + " << c << ") = " << sum << endl;
      return 0;
      }

      Reply

5. #include
   #include

   double f(double x) {
   // Define the function f(x) here
   return /* the value of f(x) */;
   }

   int main() {
   double z;
   std::cout <> from;

   double x, Y;
   if (from > 0) {
   x = -3 * pow(from, 2);
   y = 2 * f(x) * (asin(x) + (double)exp(-x – 3));
   std::cout < 0, x = ” << x << " and y = " << Y << std::endl;
   } else {
   x = -3 * pow(from, 2);
   y = 2 * f(x) * (asin(x) + (double)exp(-x – 3));
   std::cout << "For Z <= 0, x = " << x << " and y = " << Y << std::endl;
   }

   return 0;
   }

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6. Create function module (Modular programming in C++) with processing algorithms
   one-dimensional arrays for int types, float (using the function overload mechanism). It is all
   necessary data for functions should be passed to them as parameters.
   The use of global variables and I/O operations in functions is not
   allowed.

   —————-
   § filling with random values;
   § calculation of the sum, products of array elements in a given index range
   using predicate functions;
   § insertion and deletion of array element/elements based on shift algorithms;
   § array sorting, at least three quadratic complexity class algorithms;
   § linear search algorithm in the implementation of tasks: search for maximum and minimum
   elements;
   § binary search algorithm for a given key in an array;
   § counting the number of elements with a specified characteristic (positive,
   negative, zero, multiples of t), using predicate functions
   § input/output of array elements, file input/output of array elements
   file I/O, use text and binary files.

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7. To solve this problem, you can use the following Python code:

   python
def f(x):
return 2 * (math.sin(x) + math.e ** (-x - 3))

   def U(z):
if z > 0:
x = -3 * z
elif z <= 0:
x = -3 * z ** 2
return f(x)


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8. // Welcome to the fucking calculator!
   // Update! Version 1.1 ( 27.02.2023 20:15)
   //~Added ” Answer “.

   //Update! Version 1.2 ( 27.01.2023 20:48 )
   //~Instruction added(in English!).
   //~Copyrights added.

   //Update! Version 1.3 (27.02.2023 21.49)
   //Version 1.3 (27.02.2023 21.49)
   //~Added frame with instructions
   //~Added calculation of square and cubic powers
   //~Copyrights removed.

   //global update!!! Version 1.4 (27.02.2023 22.52)
   //~Added display of calculator actions.
   //~Phrase ” Answer ” removed.
   //~Code is smaller, because of which the compiler needs less processing time.
   //~The exponentiation system has been redesigned. Now you can raise numbers to any degree. (read the instructions)

   //Update! Version 1.5 (28.02.2023 0.42)
   //~Added square root calculation.
   //~Added calculation of the Pythagorean Theorem.
   //~Thread altered.
   //Update! Version 1.5.1 (28.02.2023 19:50)
   //~Rewritten code(replacing if and else on a switch)
   //~”Answer” returned under the decision line.

   //Update! Version 1.6 ( in developing )

   //Ideas:
   //~Adding a system of variables for certain tasks
   //~Translating the code into the application ( i fucking know, how to do it, to help!!! )
   //~Introduction of such formulas, how:
   // 1) Discriminator
   // 2) Perimeter, figure area

   #include
   #include
   using namespace std;

   int main()
   {
   cout << " ___________________________________________________________" << endl;
   cout << "|SchwarzeCalculator |" << endl;
   cout << "|Instruction: |" << endl;
   cout << "|To use the calculator, enter 3 digits separated by a space.|" << endl;
   cout << "|Example: |" << endl;
   cout << "|5 3 2 |" << endl;
   cout << "|5 – the first number. |" << endl;
   cout << "|3 – the second number. |" << endl;
   cout << "|2 – action code. |" << endl;
   cout << "|Action codes: |" << endl;
   cout << "|1 – addition. |" << endl;
   cout << "|2 – subtraction. |" << endl;
   cout << "|3 – multiplication. |" << endl;
   cout << "|4 – division. |" << endl;
   cout << "|5 – exponentiation (first number – base of degree, second |" << endl;
   cout << "|number – exponent |" << endl;
   cout << "|6 – square root |" << endl;
   cout << "|7 – Pyphagorean theorem ( both numbers – cathets |" << endl;
   cout << "|8 – Pyphagorean theorem ( first number – hypitenuse, second|" << endl;
   cout << "| number – cathetus |" << endl;
   cout << "|___________________________________________________________|" << endl;
   cout << "Enter the details below :" <> a;
   cin >> b;
   cin >> from;
   switch (from) {
   case 1:
   cout << a << "+" << b << "=" << a + b << endl;
   break;
   case 2:
   cout << a << "-" << b << "=" << a – b << endl;
   break;
   case 3:
   cout << a << "*" << b << "=" << a * b << endl;
   break;
   case 4:
   cout << a << "/" << b << "=" << a / b << endl;
   break;
   case 5:
   cout << a << "^" << b << "=" << pow(a, b) << endl;
   break;
   case 6:
   cout << "sqrt" << a << "=" << sqrt(a) << endl;
   break;
   case 7:
   cout << a << "^2" << "+" << b << "^2" << "=" << sqrt(pow(a, 2) + pow(b, 2)) << "^2" << endl;
   break;
   case 8:
   cout << a << "^2" << "-" << b << "^2" << "=" << sqrt(pow(a, 2) – pow(b, 2)) << "^2" << endl;
   break;
   }
   cout << "—————————————" << endl;
   cout << "Answer:";
   switch (from) {
   case 1:
   cout << a + b << endl;
   break;
   case 2:
   cout << a – b << endl;
   break;
   case 3:
   cout << a * b << endl;
   break;
   case 4:
   cout << a / b << endl;
   break;
   case 5:
   cout << pow(a, b) << endl;
   break;
   case 6:
   cout << sqrt(a) << endl;
   break;
   case 7:
   cout << sqrt(pow(a, 2) + pow(b, 2)) << "^2" << endl;
   break;
   case 8:
   cout << sqrt(pow(a, 2) – pow(b, 2)) << "^2" << endl;
   break;
   }
   cout << " " << endl;
   cout << "ver. 1.5.1" << endl;
   cout << "Code by Schwarze Kydelyok" << endl;
   cout << "Compiler program – MSVS 2022";
   cout << " " << endl;
   return 0;
   }

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   1. iostream and cmath))))

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