The basics of programming in c++ for beginners

Tasks: Select if and else statements in c ++

After reading the lesson aboutSelect if and else statements, go to practice. As usual, I ask you to try to solve all tasks independently, and only then look at proposed us decision.

1. The first task is interesting and fairly simple. But the code will succeed long. This task came up with our teachers of computer Academy. The idea was to – how to get beginning students suffer with writing code, to scribbling was more )))  The task: The user enters the number of the 1 to 9999 (the amount of the issuance of an ATM). It should display the words entered by the amount and in the end to write the name of the currency with the correct ending. For example: 7431 – seven thousand four hundred thirty-one Dollars_, 2149 – two thousand one hundred forty-nine dollars_, 15 – fifteen dollars_, 3 – three dollars_. To solve this task you will need to use the operator % (remainder of the division). Read about it in an article, you can Arithmetic operations in C ++  . Start!

2.  The user enters the serial number of the finger. It should show its name on the screen.

 3. Another challenge for yourself solutions. You must write a program, which checks the user on the knowledge of the multiplication table. The user enters two single-digit numbers. The program asks the question: the result of multiplying the first day of the second.  The user must enter a response and see on the screen is correct or not, he said,. If not– show yet and the correct result.

Those who can not cope – ask questions in the comments.

369 thoughts on “Tasks: Select if and else statements in c ++”

  1. #include
    #include

    using namespace std;

    int main(){
    setlocale(LC_ALL,”Russian”);
    int a,b,user;
    cout <> a >> b;
    cout <> user;
    if (a * b == user){
    cout << "Верно!";
    }
    else {
    cout << "Не верно! Correct answer: " << a * b << endl;
    }
    return 0;
    }

    Reply

  2. #include “stdafx.h”
    #include

    using namespace std;

    int main()
    {
    setlocale(LC_ALL, “rus”);
    int a;
    int user;
    int b;
    cout << "Введите первое число " <> a;
    cout << "Введите второе число " <> b;
    cout << "Введите ответ "<> user;
    if (a*b == user) {
    cout << "Верно" << endl;
    }
    else {
    cout << " not right!Correct answer " << a * b << endl;
    }

    system("pause");
    return 0;
    }

    Reply

  3. I do not get you, Why take the remainder of the division %. Why is enough to do so:

    if ((cash / 1000) == 9)
    {
    cout << "Девять тысяч ";
    }
    else if ((cash / 1000) == 8)
    {
    cout << "Восемь тысяч ";
    }
    and so on…

    Reply

  4. #include
    using namespace std;
    void main()
    {
    setlocale(LC_ALL,”rus”);
    int a;
    cout <> a;

    int b;
    cout <> b;

    int proi;
    cout << "Сколько будет число a умножить на число b?" <> manu;

    int c;
    c = a * b;
    if(proi==c)
    {
    cout << "Ответ верный" << endl;
    }
    else
    {
    cout << "Ответ неверный" << endl;
    }

    }

    Reply

  5. #include

    using namespace std;

    int main()
    {
    setlocale(LC_ALL, “rus”);

    int a,b,result;

    cout <> a;

    cout <> b;

    cout <> result;

    int sum=a*b;
    if (sum == result) {
    cout << " \n CORRECT RESPONSE!\n";
    }
    else {
    cout << " \n Wrong answer. Correct answer: " << a * b;
    }
    return 0;
    }

    Reply

  6. I got here so)
    #include “stdafx.h”
    #include

    using namespace std;

    int main()
    {
    int x, Y,Others,c;

    setlocale(LC_ALL, “rus”);
    do {
    cout << "Введите 2 number" <> x;
    cin >> Y;
    ym = x * Y;
    cout << "Сколько будет " << x << "*" << Y <> c;
    if (c == ym) {
    cout << "Молодец!" << endl;
    }
    else cout << "Неа, Here is the answer" << Others << endl;
    } while (c != etc.);
    return 0;
    }

    Reply

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