Tasks and Solutions: A for loop in c ++

Once you begin to tasks, therefore already know what for loop. Let's look at a few of the tasks, solution in which it is applied, and, thereby, strengthen the knowledge gained. Programming practice– the best way to deal with the material and store information for a long time.

1. Write a program, that will show on the screen the number of the square, entered by the user. The user has to decide for himself – exit the program or continue writing. (Tip – You must run an infinite loop, which provide for termination of his, upon the occurrence of certain conditions).

Show code

[crayon-69cab61760d7d034223758/]

В задаче, as you can see, provided for continuation of the work, вне зависимости в каком регистре введена буква Y (в нижнем или в верхнем).

Result:

2. In the gym every day comes a certain number of visitors. It should prompt the user to enter such data: how many people visited the gym for the day, enter the age of each visitor and ultimately show the age of the oldest and the youngest of them, as well as to calculate the average age of visitors.

Show code

#include <iostream>
using namespace std;
int main()
{
	setlocale(LC_ALL, "rus");

	int age = 0; // будет вводить пользователь
	int maxAge = 0; // для записи максимального количества лет
	int minAge = 100; // для записи минимального количества лет
	int sum = 0; // общая сумма для расчета среднего   
	int average = 0; // для записи среднего возраста посетителей
	int amount = 0; // количество посетителей спортзала
	
	cout << "Введите количество посетителей спортзала: ";
	cin >> amount;

	for (int i = 0; i < amount; i++)
	{
		cout << "Введите возраст " << i + 1 << "-го посетителя: "; // запрос на введение числа
		cin >> age;
		
		if (age > maxAge) // если оно больше, чем хранит переменная  max
			maxAge = age; // записываем в неё это число 
		if (age < minAge) 
			minAge = age;

		sum += age; // накопление общей суммы
	}
	
	average = sum / amount; // подсчет среднего возраста

	cout << "\nСредний возраст всех посетителей: " << average << endl;
	cout << "\nСамый взрослый: " << maxAge << endl;
	cout << "\nСамый молодой: " << minAge << endl;

	return 0;
}

#include <iostream>

using namespace std;

int main()

{

setlocale(LC_ALL, "rus");

int age = 0; // будет вводить пользователь

int maxAge = 0; // для записи максимального количества лет

int minAge = 100; // для записи минимального количества лет

int sum = 0; // общая сумма для расчета среднего

int average = 0; // для записи среднего возраста посетителей

int amount = 0; // количество посетителей спортзала

cout << "Введите количество посетителей спортзала: ";

cin >> amount;

for (int i = 0; i < amount; i++)

{

cout << "Введите возраст " << i + 1 << "-го посетителя: "; // запрос на введение числа

cin >> age;

if (age > maxAge) // если оно больше, чем хранит переменная max

maxAge = age; // записываем в неё это число

if (age < minAge)

minAge = age;

sum += age; // накопление общей суммы

}

average = sum / amount; // подсчет среднего возраста

cout << "\nСредний возраст всех посетителей: " << average << endl;

cout << "\nСамый взрослый: " << maxAge << endl;

cout << "\nСамый молодой: " << minAge << endl;

return 0;

}

The variable min we initialized value 100, so the program can work properly. If it was initialized value 0, conditionif (age < minAge) would not satisfy the ever, asage is always more 0. Thus the value of variable minAge would always remain zero.

Result:

[crayon-69cab61760d9a412905043/]

Result:

For the job yourself, We offer you to solve a similar task. Arrange the number of visitors entering the gym and the number of hours spent by each of them in the gym. As a result, calculate and display the total amount, which customers have paid for training.

3. In stock has a certain number of boxes of apples (in this example, 15). When the car arrives for pickup, ask the user to enter, how many boxes loaded into the first car, the second and so on, until there are no more boxes of apples. Provide case, When the user enters the number of boxes more, than there is in stock.

Show code

#include <iostream>
using namespace std;

int main()
{
	setlocale(LC_ALL, "rus");

	int boxWithApples = 15; // количество ящиков на складе
	int amountBoxesForSale = 0; // количество отгружаемых ящиков

	cout << "Сейчас на складе " << boxWithApples << " ящиков с яблоками.\n\n";
	for (int i = 1;  ; i++) // счетчик i  будет считать количество машин к погрузке
	{
		cout << "Сколько ящиков загрузить в " << i << "-ю машину? ";
		cin >> amountBoxesForSale;

		if (amountBoxesForSale > boxWithApples)
		{
			cout << "\nНа складе недостаточно товара!";
			cout << "Осталось только " << boxWithApples << " ящиков\n\n";
			i--; // уменьшить счетчик на единицу
		}
		else
		{
			boxWithApples -= amountBoxesForSale; // перезаписываем значение
			cout << "Осталось " << boxWithApples << " ящиков.\n";
		}

		if (boxWithApples == 0)// если ящиков больше нет - выйти из цикла
		{ 
			cout << "Яблоки закончились! Давай до свидания!\n";
			break;
		}
	}	
	return 0;
}

#include <iostream>

using namespace std;

int main()

{

setlocale(LC_ALL, "rus");

int boxWithApples = 15; // количество ящиков на складе

int amountBoxesForSale = 0; // количество отгружаемых ящиков

cout << "Сейчас на складе " << boxWithApples << " ящиков с яблоками.\n\n";

for (int i = 1; ; i++) // счетчик i будет считать количество машин к погрузке

{

cout << "Сколько ящиков загрузить в " << i << "-ю машину? ";

cin >> amountBoxesForSale;

if (amountBoxesForSale > boxWithApples)

{

cout << "\nНа складе недостаточно товара!";

cout << "Осталось только " << boxWithApples << " ящиков\n\n";

i--; // уменьшить счетчик на единицу

}

else

{

boxWithApples -= amountBoxesForSale; // перезаписываем значение

cout << "Осталось " << boxWithApples << " ящиков.\n";

}

if (boxWithApples == 0)// если ящиков больше нет - выйти из цикла

{

cout << "Яблоки закончились! Давай до свидания!\n";

break;

}

return 0;

}

"I" count in string 21 reduced per unit, so that the next iteration of the loop to show the correct serial number of the machine.

Result:

[crayon-69cab61760da0608653826/]

"I" count in string 21 reduced per unit, so that the next iteration of the loop to show the correct serial number of the machine.

Result:

If you have questions, please contact us in the comments.

161 thoughts on “Tasks: A for loop in c ++”

Andrey Tokarev says:
31.05.2015 at 20:24
#include #include using namespace std;
int main() { setlocale(LC_ALL, "rus"); int x = 0; int y = 0; int min = 1000; int max = 0; int sum = 0; int srd = 0;
cout <> x; int z = x; for (x; (x > 0); x--)
{ cout <> y; sum = sum + y; if (min > y) min = y;
if (max < y) max = y; } srd = sum / z; cout << "Максимальный возраст - " << max << endl; cout << "Минимальный возраст - " << min << endl; cout << "Средний возраст - " << srd << endl; _getch(); return 0; }
Andrey Tokarev says:
01.06.2015 at 09:12
but the third task didn’t work out
#include #include using namespace std;
int main() { setlocale(LC_ALL, "rus"); int y = 0; int x = 0; cout << x; for ( ;;) { cout << y; x = x - y; if (x = 0) { break; } if (x < 0) { x = x + y; cout << "Введено недопустимо большое значение. Начните ввод для крайней машины заного. \n "; continue; }
else { x = x - y; cout << "У вас осталось " << x << " ящиков \n";
}
} _getch(); return 0; }
what's the mistake?
1. SK92 says:
  05.10.2015 at 14:39
  There is an error in your code at this point if (x = 0). I.e., in any case, x will not be negative, and will be constantly equal 0.
Marjan Puzdrak says:
13.09.2015 at 21:10
This is how I got problem N3:
________________________
#include #include using namespace std; int main () { int a,h,b,c,k,p,v,g,n; a=0;//ящикoв setlocale(LC_ALL, "rus"); b=0;//машини n=0;//ящики v=0;//лишились k=0; g=0; h=0; cout <<"Введите количество ящиков"<>a; cout <<"Введите количество машин"<>b;
for (c=1;c<=b;c++) { :check_1 cout <<"Сколько ящиков поставить в "<<c<<"-ю машину?"<>n; g+=n;// if (a<g) { g-=n; for (;;) { cout <<"Недостаточно ящиков"<<endl; cout <<"Сколько ящиков поставить в "<<c<<"-ю машину?"<>p; g+=p;// } if (a>g) { :check_1 } else g-=p; goto check; } } } if (g<a) { cout <<"Ошибка!Нехватка машин!У вас осталось "<<a-g<<" ящиков"<<endl; } else cout <<"15 ящиков распределено по машинах"<<endl;
system ("pause"); return 0; }
1. Olej says:
  15.09.2015 at 10:18
  > This is how I got problem N3:
  Seeing this without markings – it's all the same, if only I could write all the code in one line. The code even in such a record will be compiled and executed, but that doesn't mean, that someone will read it.
2. Olej says:
  16.09.2015 at 14:46
  > This is how I got problem N3:
  Would you at least compile the code?, ran it through the computer, before showing it – there will be just a lot syntactic errors. Therefore, talk about “it worked” – won't suit you ;-).
Stiletto says:
16.09.2015 at 10:19
for (;;) – Where is the exit from the loop??
Or was he there, but the portal ate?
user says:
19.09.2015 at 05:08
Why not write something like this? : int minAge = 100;
Can this be done :
int minAge = 0
if (age < minAge || age == 0)
Otherwise it’s not known, maybe life expectancy will increase in the future..
1. Olej says:
  20.09.2015 at 12:04
  > Can this be done :
  Can…
  But pay attention to this, what always when selected in sequence (array, list, etc.) element according to some criterion: min, max, … any – есть 2 different approaches:
  1. take as the initial value a value that is clearly not suitable for this (then, what is in your example … 100, 0, …);
  2. take as initial value first sequence element, and it's too much to lead, starting from next, 2-it elements.
  1. user says:
    21.09.2015 at 17:45
    .. then set the condition for the second element..
    Well, whose brains are twisted. In general, this is the attractiveness of this business..
qreator says:
28.10.2015 at 11:25
I somehow managed the 3rd task differently
#include
using namespace std;
int main()
{
you nNumBoxPerCar, nNumBox=0, i=1, nOstatokBox=15;
for ( ;nNumBox < 15 ; i )
{
cout << "Сколько ящиков загрузить в машину " << i <> nNumBoxPerCar;
nNumBox = nNumBox + nNumBoxPerCar;
if (nNumBox >= 15)
{
nOstatokBox = (15 – nNumBox) + nNumBoxPerCar;
break;
}
}
cout << "Ящики закончились. Moreover, we managed to load the last machine: "
<< nOstatokBox << "\n";
}
Vova Ovrutsky says:
31.10.2015 at 17:37
I solved the first problem differently.
using namespace std;
int main()
{
setlocale(LC_ALL, “rus”);
int number = 0;
bool Continue = 0;
for (int i = 0; i < 1; i )
{
cout <> number;
cout << endl;
cout << "Квадрат числа " << number << " = " << number*number << endl;
cout <> Continue;
if (Continue == 1)
i–;
}
system(“pause”);
return 0;
}
an_zh says:
05.02.2016 at 14:46
task №3
awry, but the main thing is the meaning and the result…
#include using namespace std; int main() { int i=0,a,b; char x; cout<<a; for(;;) { i+=1; cout<<i<<b; if (a>b) { a-=b; cout<<"Na sklade ostatok = "<<a<<endl; } else if (a<b) { cout<<"Na sklade otalos = "<<a<<endl;
cout<<"zagruzat - "<<a<<"jachikov?";
cout<<x; if (x=='y') { cout<<"zagruzili ostatok - "<<a; break; } else if (x=='n') { cout<<"izvenite za neudobstvo DOSVIDANIE"; } } else if (a==b) { cout<<"Na sklade ostalos = 0"<<endl; break; } } return 0; }

Tasks: A for loop in c ++

161 thoughts on “Tasks: A for loop in c ++”

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