Tasks: A for loop in c ++

Once you begin to tasks, therefore already know what for loop. Let's look at a few of the tasks, solution in which it is applied, and, thereby, strengthen the knowledge gained. Programming practice– the best way to deal with the material and store information for a long time.

1. Write a program, that will show on the screen the number of the square, entered by the user. The user has to decide for himself – exit the program or continue writing. (Tip – You must run an infinite loop, which provide for termination of his, upon the occurrence of certain conditions).

Show code

[crayon-69ca9df4b78f1647013667/]

В задаче, as you can see, provided for continuation of the work, вне зависимости в каком регистре введена буква Y (в нижнем или в верхнем).

Result:

2. In the gym every day comes a certain number of visitors. It should prompt the user to enter such data: how many people visited the gym for the day, enter the age of each visitor and ultimately show the age of the oldest and the youngest of them, as well as to calculate the average age of visitors.

Show code

#include <iostream>
using namespace std;
int main()
{
	setlocale(LC_ALL, "rus");

	int age = 0; // будет вводить пользователь
	int maxAge = 0; // для записи максимального количества лет
	int minAge = 100; // для записи минимального количества лет
	int sum = 0; // общая сумма для расчета среднего   
	int average = 0; // для записи среднего возраста посетителей
	int amount = 0; // количество посетителей спортзала
	
	cout << "Введите количество посетителей спортзала: ";
	cin >> amount;

	for (int i = 0; i < amount; i++)
	{
		cout << "Введите возраст " << i + 1 << "-го посетителя: "; // запрос на введение числа
		cin >> age;
		
		if (age > maxAge) // если оно больше, чем хранит переменная  max
			maxAge = age; // записываем в неё это число 
		if (age < minAge) 
			minAge = age;

		sum += age; // накопление общей суммы
	}
	
	average = sum / amount; // подсчет среднего возраста

	cout << "\nСредний возраст всех посетителей: " << average << endl;
	cout << "\nСамый взрослый: " << maxAge << endl;
	cout << "\nСамый молодой: " << minAge << endl;

	return 0;
}

#include <iostream>

using namespace std;

int main()

{

setlocale(LC_ALL, "rus");

int age = 0; // будет вводить пользователь

int maxAge = 0; // для записи максимального количества лет

int minAge = 100; // для записи минимального количества лет

int sum = 0; // общая сумма для расчета среднего

int average = 0; // для записи среднего возраста посетителей

int amount = 0; // количество посетителей спортзала

cout << "Введите количество посетителей спортзала: ";

cin >> amount;

for (int i = 0; i < amount; i++)

{

cout << "Введите возраст " << i + 1 << "-го посетителя: "; // запрос на введение числа

cin >> age;

if (age > maxAge) // если оно больше, чем хранит переменная max

maxAge = age; // записываем в неё это число

if (age < minAge)

minAge = age;

sum += age; // накопление общей суммы

}

average = sum / amount; // подсчет среднего возраста

cout << "\nСредний возраст всех посетителей: " << average << endl;

cout << "\nСамый взрослый: " << maxAge << endl;

cout << "\nСамый молодой: " << minAge << endl;

return 0;

}

The variable min we initialized value 100, so the program can work properly. If it was initialized value 0, conditionif (age < minAge) would not satisfy the ever, asage is always more 0. Thus the value of variable minAge would always remain zero.

Result:

[crayon-69ca9df4b795a551189124/]

Result:

For the job yourself, We offer you to solve a similar task. Arrange the number of visitors entering the gym and the number of hours spent by each of them in the gym. As a result, calculate and display the total amount, which customers have paid for training.

3. In stock has a certain number of boxes of apples (in this example, 15). When the car arrives for pickup, ask the user to enter, how many boxes loaded into the first car, the second and so on, until there are no more boxes of apples. Provide case, When the user enters the number of boxes more, than there is in stock.

Show code

#include <iostream>
using namespace std;

int main()
{
	setlocale(LC_ALL, "rus");

	int boxWithApples = 15; // количество ящиков на складе
	int amountBoxesForSale = 0; // количество отгружаемых ящиков

	cout << "Сейчас на складе " << boxWithApples << " ящиков с яблоками.\n\n";
	for (int i = 1;  ; i++) // счетчик i  будет считать количество машин к погрузке
	{
		cout << "Сколько ящиков загрузить в " << i << "-ю машину? ";
		cin >> amountBoxesForSale;

		if (amountBoxesForSale > boxWithApples)
		{
			cout << "\nНа складе недостаточно товара!";
			cout << "Осталось только " << boxWithApples << " ящиков\n\n";
			i--; // уменьшить счетчик на единицу
		}
		else
		{
			boxWithApples -= amountBoxesForSale; // перезаписываем значение
			cout << "Осталось " << boxWithApples << " ящиков.\n";
		}

		if (boxWithApples == 0)// если ящиков больше нет - выйти из цикла
		{ 
			cout << "Яблоки закончились! Давай до свидания!\n";
			break;
		}
	}	
	return 0;
}

#include <iostream>

using namespace std;

int main()

{

setlocale(LC_ALL, "rus");

int boxWithApples = 15; // количество ящиков на складе

int amountBoxesForSale = 0; // количество отгружаемых ящиков

cout << "Сейчас на складе " << boxWithApples << " ящиков с яблоками.\n\n";

for (int i = 1; ; i++) // счетчик i будет считать количество машин к погрузке

{

cout << "Сколько ящиков загрузить в " << i << "-ю машину? ";

cin >> amountBoxesForSale;

if (amountBoxesForSale > boxWithApples)

{

cout << "\nНа складе недостаточно товара!";

cout << "Осталось только " << boxWithApples << " ящиков\n\n";

i--; // уменьшить счетчик на единицу

}

else

{

boxWithApples -= amountBoxesForSale; // перезаписываем значение

cout << "Осталось " << boxWithApples << " ящиков.\n";

}

if (boxWithApples == 0)// если ящиков больше нет - выйти из цикла

{

cout << "Яблоки закончились! Давай до свидания!\n";

break;

}

return 0;

}

"I" count in string 21 reduced per unit, so that the next iteration of the loop to show the correct serial number of the machine.

Result:

[crayon-69ca9df4b798c934353309/]

"I" count in string 21 reduced per unit, so that the next iteration of the loop to show the correct serial number of the machine.

Result:

If you have questions, please contact us in the comments.

161 thoughts on “Tasks: A for loop in c ++”

The second and more 3 tasks:

cout << "\t Задача 2 (дополнительно) \n";
		cout << "---------------- \n";
		int amountHours = 0;//Количество часов_задача2доп
		int amountHumans_z2 = 0;//Количество посетителей_задача2доп
		int amountGold = 0;//Количество денег_задача2доп
		int sum_g = 0;//Сумма денег (в цикле)_задача2доп
		int hs = 0;//Стоимость часа_задача2доп
		cout <> amountHumans_z2;
			for (int k=1; k<=amountHumans_z2; k++)
			{
				cout << "Посетитель " << k <> amountHours;
					if (amountHours == 1) cout << "час \n";
					else if (amountHours == 2 || amountHours == 3 || amountHours == 4) cout << "часа \n";
					else cout << "часов \n";
					sum_g += amountHours;
			}
		cout <> hs;
		amountGold = sum_g*hs;
		cout << "Денег получено: \n" << amountGold << endl;

		cout << "\t Задача 3 \n";
		cout << "---------------- \n";
		int kolBox = 0; //Количество ящиков
		int kolLoadBox = 0;//Количество загружаемых ящиков
		cout <> kolBox;
			for (;;)
			{
				cout <> kolLoadBox;
				kolBox = kolBox - kolLoadBox;		
				cout << "Ящиков осталось на складе: " << kolBox << endl;
				if (kolBox <=0) break;
			}
			if (kolBox == 0) cout << "Ящики кончились \n";
			else if (kolBox<0) cout << "Столько ящиков нет на складе \n";

cout << "\t Задача 2 (дополнительно) \n";

cout << "---------------- \n";

int amountHours = 0;//Количество часов_задача2доп

int amountHumans_z2 = 0;//Количество посетителей_задача2доп

int amountGold = 0;//Количество денег_задача2доп

int sum_g = 0;//Сумма денег (в цикле)_задача2доп

int hs = 0;//Стоимость часа_задача2доп

cout <> amountHumans_z2;

for (int k=1; k<=amountHumans_z2; k++)

{

cout << "Посетитель " << k <> amountHours;

if (amountHours == 1) cout << "час \n";

else if (amountHours == 2 || amountHours == 3 || amountHours == 4) cout << "часа \n";

else cout << "часов \n";

sum_g += amountHours;

}

cout <> hs;

amountGold = sum_g*hs;

cout << "Денег получено: \n" << amountGold << endl;

cout << "\t Задача 3 \n";

cout << "---------------- \n";

int kolBox = 0; //Количество ящиков

int kolLoadBox = 0;//Количество загружаемых ящиков

cout <> kolBox;

for (;;)

{

cout <> kolLoadBox;

kolBox = kolBox - kolLoadBox;

cout << "Ящиков осталось на складе: " << kolBox << endl;

if (kolBox <=0) break;

}

if (kolBox == 0) cout << "Ящики кончились \n";

else if (kolBox<0) cout << "Столько ящиков нет на складе \n";

Muhammadjon says:
14.01.2017 at 21:04
#include
using namespace std;
int main()
{
int base;
int power;
long long result=1;
cout<>base>>power;
for(int i=1;i<=power;i )
{
result*base;
}
cout<<"Result is"<<result;
return 0;
}
Reply
Alexander says:
15.02.2017 at 14:00
Your program for the third task will not work correctly, if the number of loaded boxes is more than what is in stock.
cout kolLoadBox;
kolBox = kolBox – kolLoadBox; you might succeed here “-”
cout << "Ящиков осталось на складе: " << kolBox << endl;
if (kolBox <=0) break;
for example: kolBox = 15
the first car requested 10
kolBox = kolBox – kolLoadBox
left 5 boxes, the next car is asking 7
you will have the count and it will be in stock -2 box.
Reply

//задача 1 //

#include 

#include 


int main (){

	setlocale(LC_ALL, "Rus");

	int a,b;

	do {

		std::cout << "Введите число чтобы возвести в квадрат:" <> a;

		std::cout << a*a <<std::endl;

		std::cout <<"Вы хотите продолжить? 1 - yes 2 - no " <> b;

	} while(b == 1);

	exit(0);

	_getch();
	
	return 0;
}

//задача 1 //

#include

int main (){

setlocale(LC_ALL, "Rus");

int a,b;

do {

std::cout << "Введите число чтобы возвести в квадрат:" <> a;

std::cout << a*a <<std::endl;

std::cout <<"Вы хотите продолжить? 1 - yes 2 - no " <> b;

} while(b == 1);

exit(0);

_getch();

return 0;

}

Marina says:
21.11.2016 at 13:39
please help make!
Skier, starting exercise, on the first day ran n km. Every day he increased the mileage on m% from the previous day's run. How many kilometers he will run for k days.
Reply
1. Olej says:
  21.11.2016 at 15:19
  KM = sum( i = 0, k-1, n * (1+0.01*m)**k )
  And write this down cycle.
  Reply
2. Savior says:
  08.12.2016 at 14:31
  double n;
  double m;
  Int k, S;
  cin>>n>>m>>k;
  for (i = 1; i < =k; i )
  S=((n + m)+m)*k;
  cout<<k;
  return ;
  }
  Reply
  1. Olej says:
    08.12.2016 at 16:50
    You would, before writing, We tested the performance of the, that write… :-(
Aleksey says:
21.11.2016 at 15:36
double n;
double m;
Int k;
for (i = 1; i < k; i ) {
n += (n * m);
}
Reply
1. Olej says:
  21.11.2016 at 15:46
  double km = 0., mn = 1.; for( int i = 0; i < k; i++ ) { km += n * mn; mn *= ( 1. + .01 * m ); }
  Reply

task N3

#include 
using namespace std;
int main()
{
	int box=0;
	int bl=0;
	int i=0;
	
	cout<>box;
	
	for(;;)
	{
		i++;
		cout<<"Truck N "<<i<<":";
		cout<<"\n"<>bl;
		if(bl>box)
		{
		cout<<"Sorry, we don't have enough, please come later!!";
		i--;
		break;
		}
		else
		box=box-bl;
		if(box <= 0)
		break;
	}
	cout<<"\n\n"<<"Boxes remain: "<<box<<"\n";
	cout<<"Trucks: "<<i<<"\n\n";
	return 0;
	
}

#include

using namespace std;

int main()

{

int box=0;

int bl=0;

int i=0;

cout<>box;

for(;;)

{

i++;

cout<<"Truck N "<<i<<":";

cout<<"\n"<>bl;

if(bl>box)

{

cout<<"Sorry, we don't have enough, please come later!!";

i--;

break;

}

else

box=box-bl;

if(box <= 0)

break;

}

cout<<"\n\n"<<"Boxes remain: "<<box<<"\n";

cout<<"Trucks: "<<i<<"\n\n";

return 0;

}

Artur says:
22.11.2016 at 13:52
String 9,10
C++
cout<>box;
1
cout<>box;
Reply
1. Artur says:
  22.11.2016 at 13:53
  cout<>box;
Olej says:
23.11.2016 at 20:20
editor site spoils code entry – eats characters between the opening and closing angle brackets.
So I 100 once he wrote in different themes: Do not write your code here!
Why did you write the code here?
Want to brag?
Or you want to praise?
So not praise you for that: at your place … as well as all other students – very mediocre ;-).
And if you want your code pokritikoval, then please contact us here:
http://rus-linux.net/forum/viewforum.php?f=31
Reply

Alex says:
16.01.2017 at 12:34
Why is a sign not of equality can not understand the first task :( if (exit != 'And’ && exit != 'Y').
Reply
1. Olej says:
  16.01.2017 at 18:46
  Because if you enter something, anything Besides 'Y’ или 'Y’ (не 'and’ and не 'Y') – then you have not yet matured to exit the program.
  Reply
  1. Alexander says:
    15.02.2017 at 14:08
    On the contrary, here we mean , to continue you must enter exactly ‘y’’ or 'Y', if you enter anything except 'y' or 'Y', then the program will finish executing.
2. Alexander says:
  15.02.2017 at 13:50
  you can write it like this, if (exit == ‘n’ && exit == ‘N’)
  Reply
What says:
03.02.2017 at 17:03
Hi! I would like to know where to find more problems?
Reply
Alex says:
05.02.2017 at 17:57
Given chislo.Vybrosit natures of the record of this number of digits 3 ,leaving unchanged the rest of the order of numbers, if no number 3, then output a predetermined number of(Help ,you are welcome.
Reply

Tasks: A for loop in c ++

161 thoughts on “Tasks: A for loop in c ++”

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