Once you begin to tasks, therefore already know what for loop. Let's look at a few of the tasks, solution in which it is applied, and, thereby, strengthen the knowledge gained. Programming practice– the best way to deal with the material and store information for a long time.
1. Write a program, that will show on the screen the number of the square, entered by the user. The user has to decide for himself – exit the program or continue writing. (Tip – You must run an infinite loop, which provide for termination of his, upon the occurrence of certain conditions).
Show code
Задача: оператор for 1
C++
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#include <iostream>
usingnamespacestd;
intmain()
{
setlocale(LC_ALL,"rus");
intdigit=0;// число для расчета
charexit='y';// для выхода или продолжения
for(;;)
{
cout<<"Введите число: ";
cin>>digit;
cout<<"Квадрат "<<digit<<" = "<<digit*digit;
cout<<"\nПродолжить ввод чисел - Y, Выйти - N: ";
cin>>exit;// выбор пользователя
if(exit!='y'&&exit!='Y')
break;// прервать цикл
}
return0;
}
В задаче, as you can see, provided for continuation of the work, вне зависимости в каком регистре введена буква Y (в нижнем или в верхнем).
Result:
2. In the gym every day comes a certain number of visitors. It should prompt the user to enter such data: how many people visited the gym for the day, enter the age of each visitor and ultimately show the age of the oldest and the youngest of them, as well as to calculate the average age of visitors.
Show code
Задача: оператор for 2
C++
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#include <iostream>
usingnamespacestd;
intmain()
{
setlocale(LC_ALL,"rus");
intage=0;// будет вводить пользователь
intmaxAge=0;// для записи максимального количества лет
intminAge=100;// для записи минимального количества лет
intsum=0;// общая сумма для расчета среднего
intaverage=0;// для записи среднего возраста посетителей
intamount=0;// количество посетителей спортзала
cout<<"Введите количество посетителей спортзала: ";
cin>>amount;
for(inti=0;i<amount;i++)
{
cout<<"Введите возраст "<<i+1<<"-го посетителя: ";// запрос на введение числа
cin>>age;
if(age>maxAge)// если оно больше, чем хранит переменная max
maxAge=age;// записываем в неё это число
if(age<minAge)
minAge=age;
sum+=age;// накопление общей суммы
}
average=sum/amount;// подсчет среднего возраста
cout<<"\nСредний возраст всех посетителей: "<<average<<endl;
cout<<"\nСамый взрослый: "<<maxAge<<endl;
cout<<"\nСамый молодой: "<<minAge<<endl;
return0;
}
The variable min we initialized value 100, so the program can work properly. If it was initialized value 0, conditionif (age < minAge) would not satisfy the ever, asage is always more 0. Thus the value of variable minAge would always remain zero.
Result:
For the job yourself, We offer you to solve a similar task. Arrange the number of visitors entering the gym and the number of hours spent by each of them in the gym. As a result, calculate and display the total amount, which customers have paid for training.
3. In stock has a certain number of boxes of apples (in this example, 15). When the car arrives for pickup, ask the user to enter, how many boxes loaded into the first car, the second and so on, until there are no more boxes of apples. Provide case, When the user enters the number of boxes more, than there is in stock.
Show code
Задача: оператор for 3
C++
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#include <iostream>
usingnamespacestd;
intmain()
{
setlocale(LC_ALL,"rus");
intboxWithApples=15;// количество ящиков на складе
intamountBoxesForSale=0;// количество отгружаемых ящиков
cout<<"Сейчас на складе "<<boxWithApples<<" ящиков с яблоками.\n\n";
for(inti=1;;i++)// счетчик i будет считать количество машин к погрузке
{
cout<<"Сколько ящиков загрузить в "<<i<<"-ю машину? ";
cin>>amountBoxesForSale;
if(amountBoxesForSale>boxWithApples)
{
cout<<"\nНа складе недостаточно товара!";
cout<<"Осталось только "<<boxWithApples<<" ящиков\n\n";
i--;// уменьшить счетчик на единицу
}
else
{
boxWithApples-=amountBoxesForSale;// перезаписываем значение
cout<<"Осталось "<<boxWithApples<<" ящиков.\n";
}
if(boxWithApples==0)// если ящиков больше нет - выйти из цикла
{
cout<<"Яблоки закончились! Давай до свидания!\n";
break;
}
}
return0;
}
"I" count in string 21 reduced per unit, so that the next iteration of the loop to show the correct serial number of the machine.
Result:
If you have questions, please contact us in the comments.
4.4
47
161 thoughts on “Tasks: A for loop in c ++”
normalek children, I decided. And by the way the author was like a bug in the problem, type of stock is left – 65 boxes (and so on. that is, a negative number), I have no bugs)) #include using namespace std;
int main () { int a /* the amount shipped */, b = 15 / * number of stock * /; cout << "На складе " << b <> a; for (int i / * Number of vehicles * / = 1; (a > 0) && (a <= b) ; i ) { if (a == 15) { cout << "На складе не осталось ящиков"; exit (0); } b -= a; cout << "На складе " << b << " boxes, how to ship " << i <> a; if (a == b) { cout << "На складе не осталось ящиков"; exit (0); }
it seems to me too much superfluous code… 3 the task:
#include “pch.h” #include
using namespace std;
int main() { system(“chcp 1251”); system(“cls”);
cout << "На складе 15 boxes" << endl; int i=0 , max = 15, on one, sum = 0, sum1 = 0, sum2 = 0; for (;;) { cout << "Сколько погрузить в " << i + 1 << " car?" <> on one; if (on one <= max – sum) sum = sum + on one; else { cout << "Не больше чем : " << max – sum << endl; cout << "Сколько погрузить в " << i + 1 << " car?" <> on one; if (whether the max) cout << "Максимум 15!" << endl; sum1 = sum – max; sum2 = max – sum; if (sum < max) cout << " There are only " << sum2 << " boxes!" < max) { cout << " There are only " << sum1 << " boxes!" << endl; I - num; cout << " How immersed in " << i << " car?" <> on one; } i = 1; if (on one > max) cout << "Максимум 15!" << endl; else if (sum == max) break; } cout << "Вы погрузили все ящики!" << endl; cin.get(); return 0; }
I do somewhere went wrong place))) // ship boxes of apples. If not enough boxes will ship all that remains #include using namespace std;
int main() { setlocale(LC_ALL, “rus”); int box = 654; // the number of boxes of apples int unbox = 0; // as you need to unload int mach = 0; // number of cars int i = 0; cout <> mach; // enter the number of cars for (;;) // infinite loading loop (while eating apples). If not enough boxes hammered last car to dump { cout << "Есть " << box << " boxes of apples! " << "Сколько загрузить ящиков в машину № " << i + 1 <> unbox; // We determine the number of boxes to be loaded i ; // We move on to the next machine if ((box – unbox) < 0) // boxes is not enough? ship that left and complete program { cout << "Нет столько ящиков! you have requested " << unbox << ", left " << box << "!" << "\nВсе оставшиеся ящики погружены в машину № " << i << " Программа завершила работу!\n"; break; } box -= unbox; // ship boxes mach -= 1; // send machine if (mach == 0) // If the machine is not completing the cycle break; } cout << "Погрузка завершена! Until! Until!\n"; system("PAUSE"); return 0; }
int visitors; int time; int allTime = 0; int priceInHour = 50; int sum;
cout <> visitors; cout << endl; int i; for (i = 0; i < visitors; i ) { cout << "Введитеr количество часов которое провел в зале " << i + 1 <> time; cout << endl; allTime += time;
}
sum = priceInHour * allTime; cout << "Общая сумма, which visitors paid for training = " << sum << endl << endl;
You have the second job, where “Show code” below, error, written – “For the job yourself …”, there should be “For self-assignment…”. Very Good, thank you for your efforts :)
int main() { setlocale(LC_ALL, “rus”); int arr[7] = { 0, 0, 0, 100, 0, 0, 0 }; cout << "Enter the number of visitors of the gym " <> arr[0]; //number posttiteley // arr3 youngest, arr4 oldest, arr5 average age, arr6 the total amount for the calculation environment… for ( arr[1] = 0; arr[1] < arr[0]; arr[1]++ ) { cout << " Enter the age " << arr[1] + 1 << " each visitor :" <> arr[2]; //the age of each visitor if (arr[4] arr[2]) { arr[3] = arr[2]; }
arr[6] += arr[2]; } arr[5] = arr[6] / arr[0]; cout << "=========================================================" << endl; cout << " The most adult visitor – " << arr[4] << " years old " << endl; cout << " Youngest visitor – " << arr[3] << " years old " << endl; cout << " Average age of visitors " << arr[5] << " years" << endl; }
int main(){ setlocale(LC_ALL, “rus”); int a = 15;//the total number of boxes in stock int b = 0;//The number of mailboxes in submerged car for(int x = 1; ; x++){ a-= b; if(a==0){ cout<<"Ящиков на складе не осталось"; break; } cout<<"Сколько ящиков загрузить в "<<x<<"-ю машину (ящиков на складе "<<a<>b; while(1){ if(b>a){ cout<<"На складе нет столько ящиков, повторите ввод"<<endl; cout<<"Сколько ящиков загрузить в "<<x<<"-ю машину (ящиков на складе "<<a<>b; } else {break;} } } return 0; }
normalek children, I decided. And by the way the author was like a bug in the problem, type of stock is left – 65 boxes (and so on. that is, a negative number), I have no bugs))
#include
using namespace std;
int main ()
{
int a /* the amount shipped */, b = 15 / * number of stock * /;
cout << "На складе " << b <> a;
for (int i / * Number of vehicles * / = 1; (a > 0) && (a <= b) ; i )
{
if (a == 15)
{
cout << "На складе не осталось ящиков";
exit (0);
}
b -= a;
cout << "На складе " << b << " boxes, how to ship " << i <> a;
if (a == b)
{
cout << "На складе не осталось ящиков";
exit (0);
}
}
cout << "На складе нет столько ящиков";
}
I bet does not work?)
it seems to me too much superfluous code…
3 the task:
#include “pch.h”
#include
using namespace std;
int main()
{
system(“chcp 1251”);
system(“cls”);
cout << "На складе 15 boxes" << endl;
int i=0 , max = 15, on one, sum = 0, sum1 = 0, sum2 = 0;
for (;;) {
cout << "Сколько погрузить в " << i + 1 << " car?" <> on one;
if (on one <= max – sum) sum = sum + on one;
else {
cout << "Не больше чем : " << max – sum << endl;
cout << "Сколько погрузить в " << i + 1 << " car?" <> on one;
if (whether the max) cout << "Максимум 15!" << endl;
sum1 = sum – max;
sum2 = max – sum;
if (sum < max) cout << " There are only " << sum2 << " boxes!" < max) {
cout << " There are only " << sum1 << " boxes!" << endl;
I - num;
cout << " How immersed in " << i << " car?" <> on one;
}
i = 1;
if (on one > max) cout << "Максимум 15!" << endl;
else if (sum == max)
break;
}
cout << "Вы погрузили все ящики!" << endl;
cin.get();
return 0;
}
I do somewhere went wrong place)))
// ship boxes of apples. If not enough boxes will ship all that remains
#include
using namespace std;
int main()
{
setlocale(LC_ALL, “rus”);
int box = 654; // the number of boxes of apples
int unbox = 0; // as you need to unload
int mach = 0; // number of cars
int i = 0;
cout <> mach; // enter the number of cars
for (;;) // infinite loading loop (while eating apples). If not enough boxes hammered last car to dump
{
cout << "Есть " << box << " boxes of apples! " << "Сколько загрузить ящиков в машину № " << i + 1 <> unbox; // We determine the number of boxes to be loaded
i ; // We move on to the next machine
if ((box – unbox) < 0) // boxes is not enough? ship that left and complete program
{
cout << "Нет столько ящиков! you have requested " << unbox << ", left " << box << "!" << "\nВсе оставшиеся ящики погружены в машину № " << i << " Программа завершила работу!\n";
break;
}
box -= unbox; // ship boxes
mach -= 1; // send machine
if (mach == 0) // If the machine is not completing the cycle
break;
}
cout << "Погрузка завершена! Until! Until!\n";
system("PAUSE");
return 0;
}
self-reference
#include “pch.h”
#include
using namespace std;
int main() {
setlocale(0, “”);
int visitors;
int time;
int allTime = 0;
int priceInHour = 50;
int sum;
cout <> visitors;
cout << endl;
int i;
for (i = 0; i < visitors; i ) {
cout << "Введитеr количество часов которое провел в зале " << i + 1 <> time;
cout << endl;
allTime += time;
}
sum = priceInHour * allTime;
cout << "Общая сумма, which visitors paid for training = " << sum << endl << endl;
return 0;
}
You have the second job, where “Show code” below, error, written – “For the job yourself …”, there should be “For self-assignment…”. Very Good, thank you for your efforts :)
#include “pch.h”
#include
#include
#include
using namespace std;
int main() {
setlocale(LC_ALL, “rus”);
int arr[7] = { 0, 0, 0, 100, 0, 0, 0 };
cout << "Enter the number of visitors of the gym " <> arr[0]; //number posttiteley
// arr3 youngest, arr4 oldest, arr5 average age, arr6 the total amount for the calculation environment…
for ( arr[1] = 0; arr[1] < arr[0]; arr[1]++ ) {
cout << " Enter the age " << arr[1] + 1 << " each visitor :" <> arr[2]; //the age of each visitor
if (arr[4] arr[2]) {
arr[3] = arr[2];
}
arr[6] += arr[2];
}
arr[5] = arr[6] / arr[0];
cout << "=========================================================" << endl;
cout << " The most adult visitor – " << arr[4] << " years old " << endl;
cout << " Youngest visitor – " << arr[3] << " years old " << endl;
cout << " Average age of visitors " << arr[5] << " years" << endl;
}
#include
using namespace std;
int main(){
setlocale(LC_ALL, “rus”);
int a = 15;//the total number of boxes in stock
int b = 0;//The number of mailboxes in submerged car
for(int x = 1; ; x++){
a-= b;
if(a==0){
cout<<"Ящиков на складе не осталось";
break;
}
cout<<"Сколько ящиков загрузить в "<<x<<"-ю машину (ящиков на складе "<<a<>b;
while(1){
if(b>a){
cout<<"На складе нет столько ящиков, повторите ввод"<<endl;
cout<<"Сколько ящиков загрузить в "<<x<<"-ю машину (ящиков на складе "<<a<>b;
}
else {break;}
}
}
return 0;
}