Once you begin to tasks, therefore already know what for loop. Let's look at a few of the tasks, solution in which it is applied, and, thereby, strengthen the knowledge gained. Programming practice– the best way to deal with the material and store information for a long time.
1. Write a program, that will show on the screen the number of the square, entered by the user. The user has to decide for himself – exit the program or continue writing. (Tip – You must run an infinite loop, which provide for termination of his, upon the occurrence of certain conditions).
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Задача: оператор for 1
C++
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#include <iostream>
usingnamespacestd;
intmain()
{
setlocale(LC_ALL,"rus");
intdigit=0;// число для расчета
charexit='y';// для выхода или продолжения
for(;;)
{
cout<<"Введите число: ";
cin>>digit;
cout<<"Квадрат "<<digit<<" = "<<digit*digit;
cout<<"\nПродолжить ввод чисел - Y, Выйти - N: ";
cin>>exit;// выбор пользователя
if(exit!='y'&&exit!='Y')
break;// прервать цикл
}
return0;
}
В задаче, as you can see, provided for continuation of the work, вне зависимости в каком регистре введена буква Y (в нижнем или в верхнем).
Result:
2. In the gym every day comes a certain number of visitors. It should prompt the user to enter such data: how many people visited the gym for the day, enter the age of each visitor and ultimately show the age of the oldest and the youngest of them, as well as to calculate the average age of visitors.
Show code
Задача: оператор for 2
C++
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#include <iostream>
usingnamespacestd;
intmain()
{
setlocale(LC_ALL,"rus");
intage=0;// будет вводить пользователь
intmaxAge=0;// для записи максимального количества лет
intminAge=100;// для записи минимального количества лет
intsum=0;// общая сумма для расчета среднего
intaverage=0;// для записи среднего возраста посетителей
intamount=0;// количество посетителей спортзала
cout<<"Введите количество посетителей спортзала: ";
cin>>amount;
for(inti=0;i<amount;i++)
{
cout<<"Введите возраст "<<i+1<<"-го посетителя: ";// запрос на введение числа
cin>>age;
if(age>maxAge)// если оно больше, чем хранит переменная max
maxAge=age;// записываем в неё это число
if(age<minAge)
minAge=age;
sum+=age;// накопление общей суммы
}
average=sum/amount;// подсчет среднего возраста
cout<<"\nСредний возраст всех посетителей: "<<average<<endl;
cout<<"\nСамый взрослый: "<<maxAge<<endl;
cout<<"\nСамый молодой: "<<minAge<<endl;
return0;
}
The variable min we initialized value 100, so the program can work properly. If it was initialized value 0, conditionif (age < minAge) would not satisfy the ever, asage is always more 0. Thus the value of variable minAge would always remain zero.
Result:
For the job yourself, We offer you to solve a similar task. Arrange the number of visitors entering the gym and the number of hours spent by each of them in the gym. As a result, calculate and display the total amount, which customers have paid for training.
3. In stock has a certain number of boxes of apples (in this example, 15). When the car arrives for pickup, ask the user to enter, how many boxes loaded into the first car, the second and so on, until there are no more boxes of apples. Provide case, When the user enters the number of boxes more, than there is in stock.
Show code
Задача: оператор for 3
C++
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#include <iostream>
usingnamespacestd;
intmain()
{
setlocale(LC_ALL,"rus");
intboxWithApples=15;// количество ящиков на складе
intamountBoxesForSale=0;// количество отгружаемых ящиков
cout<<"Сейчас на складе "<<boxWithApples<<" ящиков с яблоками.\n\n";
for(inti=1;;i++)// счетчик i будет считать количество машин к погрузке
{
cout<<"Сколько ящиков загрузить в "<<i<<"-ю машину? ";
cin>>amountBoxesForSale;
if(amountBoxesForSale>boxWithApples)
{
cout<<"\nНа складе недостаточно товара!";
cout<<"Осталось только "<<boxWithApples<<" ящиков\n\n";
i--;// уменьшить счетчик на единицу
}
else
{
boxWithApples-=amountBoxesForSale;// перезаписываем значение
cout<<"Осталось "<<boxWithApples<<" ящиков.\n";
}
if(boxWithApples==0)// если ящиков больше нет - выйти из цикла
{
cout<<"Яблоки закончились! Давай до свидания!\n";
break;
}
}
return0;
}
"I" count in string 21 reduced per unit, so that the next iteration of the loop to show the correct serial number of the machine.
Result:
If you have questions, please contact us in the comments.
for (;;) { cout << "Введите число для возведения в квадрат: " <> a; "Enter the number to square * a;
if (a == 0) { break; }
cout << "Результат: " << a << endl; } }
"Enter the number to square() { setlocale(LC_ALL, "RUS");
"Enter the number to square 0, "Enter the number to square 0, "Enter the number to square 0, "Enter the number to square 0, minAge = 100, maxAge = 0;
cout << "Введите количество посетителей" <> "Enter the number to square;
for (int i = 0; i < "Enter the number to square; i ) { cout << "Введите возраст " << i + 1 << " visitor: " <> "Enter the number to square; "Enter the number to square;
if ("Enter the number to square > maxAge) { "Enter the number to square; } else if ("Enter the number to square < minAge) { "Enter the number to square; } } "Enter the number to square / "Enter the number to square;
cout << "Средний возраст " << "Enter the number to square << endl; cout << "Максимальный возраст " << maxAge << endl; cout << "Средний возраст " << minAge << endl; }
Easy Last Target EU #include using namespace std; int main() { int kol = 15; int a = 0; int b = 0; for (;;) { cout << "skolko yashikov pogruzit" <> a; b += a; while (b > 15) { cout << "error"; return 0; } while (b == 15) { cout << "vse yashiki pogrusheny"; return 0; }
int main() { int abox , i = 0 , inbox; cout <> Box; for (;;){ i = 1; cout << "How many boxes you want input in " << i <> inbox; if (inbox > Box){ cout << "Invalid value , you entered number grater than you have boxes. "; break; } abox -= inbox; if (Box < 0){ cout << "Invalid value , you entered number grater than you have boxes. "; break; } if (abox == 0){ cout << "Success^-^"; } cout << "Remaind boxes : " << Box << "\n"; } return 0; }
int main() { int a = 15; //availability of boxes in stock int x; //loop iterator
for (int b;a > 0;x++){ //as long as there are more boxes 15 – loop running cout <> b; // requesting the number of boxes to seize
if (b > a){ //if we ask for more than what is available cout << "Only " << a <<" box left"<< endl; } if (b <= a){ //if we ask (allowable quantity) boxes "Enter the number to square – b; //subtract boxes from the warehouse and assign a new quantity to the warehouse } if (a == 0){ //if they took all the available boxes cout << "stock is empty, you took all boxes\n"; //inform about it break; //program ends } }
#include using namespace std; int main() { int kilk = 0; int age = 0; int max = 0; int min = 100; float ser = 0; int sum = 0;
cout <> kilk;
for (int i = 0;i < kilk;i ) { cout << "Enter age of " << i + 1 <> age; if (age max) max = age;
sum = age;
} ser = sum / kilk; cout << "Average age of customers : " << to be << endl; cout << "Min age of castomers : " << min << endl; cout << "Max age of customers : " << max << endl; }
#include
using namespace std;
int main() {
setlocale(LC_ALL, “RUS”);
crayon-6247d41544235516453771/ 15, crayon-6247d41544235516453771/;
for (int i; true; i ) {
if (crayon-6247d41544235516453771/ 0) {
cout << "У вас закончились ящики, crayon-6247d41544235516453771/, till :D" << endl;
break;
}
cout << "У вас есть " << crayon-6247d41544235516453771/ << " boxes, crayon-6247d41544235516453771/ " << i + 1 << "машину" <> crayon-6247d41544235516453771/;
if (crayon-6247d41544235516453771/ > crayon-6247d41544235516453771/)
{
cout << "У вас нету столько ящиков" << endl;
continue;
}
crayon-6247d41544235516453771/;
}
}
crayon-6247d41544235516453771/() {
setlocale(LC_ALL, "RUS");
int a, result;
for (;;) {
cout << "Введите число для возведения в квадрат: " <> a;
"Enter the number to square * a;
if (a == 0) {
break;
}
cout << "Результат: " << a << endl;
}
}
"Enter the number to square() {
setlocale(LC_ALL, "RUS");
"Enter the number to square 0, "Enter the number to square 0, "Enter the number to square 0, "Enter the number to square 0, minAge = 100, maxAge = 0;
cout << "Введите количество посетителей" <> "Enter the number to square;
for (int i = 0; i < "Enter the number to square; i ) {
cout << "Введите возраст " << i + 1 << " visitor: " <> "Enter the number to square;
"Enter the number to square;
if ("Enter the number to square > maxAge) {
"Enter the number to square;
}
else if ("Enter the number to square < minAge) {
"Enter the number to square;
}
}
"Enter the number to square / "Enter the number to square;
cout << "Средний возраст " << "Enter the number to square << endl;
cout << "Максимальный возраст " << maxAge << endl;
cout << "Средний возраст " << minAge << endl;
}
I don’t understand how to loop if you enter more than what is on the fold( to help…(
#include
using namespace std;
int main()
{
setlocale(LC_ALL, “rus”);
int i = 0; //how much to ship
int after = 0; //how much is left after loading
for (int box = 15; box > 0; box – i)
{
cout << " How many boxes to ship? " <> i;
if (i > box)
{
cout << " Total in stock 15 boxes, don't fuck off, drawing " << endl;
}
else
{
after = box -= i;
cout << " Boxes left " << void swapOddAndShow << endl;
}
if (after == 0)
{
cout << "У вас не осталось ящиков " << endl;
break;
}
}
return 0;
}
And you too, when neh do you change subtitles on sites through the console, or am i the only one?
bliiiiiiiiiin, just now remembered “all in stock…” sorry
Easy Last Target EU
#include
using namespace std;
int main()
{
int kol = 15;
int a = 0;
int b = 0;
for (;;) {
cout << "skolko yashikov pogruzit" <> a;
b += a;
while (b > 15) {
cout << "error";
return 0;
}
while (b == 15) {
cout << "vse yashiki pogrusheny";
return 0;
}
}
}
// sad:(
#include
using namespace std;
int main() {
int abox , i = 0 , inbox;
cout <> Box;
for (;;){
i = 1;
cout << "How many boxes you want input in " << i <> inbox;
if (inbox > Box){
cout << "Invalid value , you entered number grater than you have boxes. ";
break;
}
abox -= inbox;
if (Box < 0){
cout << "Invalid value , you entered number grater than you have boxes. ";
break;
}
if (abox == 0){
cout << "Success^-^";
}
cout << "Remaind boxes : " << Box << "\n";
}
return 0;
}
task №3
int main()
{
int a = 15; //availability of boxes in stock
int x; //loop iterator
for (int b;a > 0;x++){ //as long as there are more boxes 15 – loop running
cout <> b; // requesting the number of boxes to seize
if (b > a){ //if we ask for more than what is available
cout << "Only " << a <<" box left"<< endl;
}
if (b <= a){ //if we ask (allowable quantity) boxes
"Enter the number to square – b; //subtract boxes from the warehouse and assign a new quantity to the warehouse
}
if (a == 0){ //if they took all the available boxes
cout << "stock is empty, you took all boxes\n"; //inform about it
break; //program ends
}
}
int a;
cout <> a;
int help = 5352;
int max = 0;
int min = 0;
float medium = 0;
int big;
int b = 0;
b = a;
int c;
for (int i = 0;i < b;i )
{
cout << "Введите возвраст" << i <> c;
if (help == 5352)
{
min = c;
}
help = 12;
if (c max)
{
max = c;
}
medium += c;
}
cout << "Max" << max << endl;
cout << "Min" << min << endl;
cout << "Middle" << float(medium/a);
#include
using namespace std;
int main()
{
int kilk = 0;
int age = 0;
int max = 0;
int min = 100;
float ser = 0;
int sum = 0;
cout <> kilk;
for (int i = 0;i < kilk;i ) {
cout << "Enter age of " << i + 1 <> age;
if (age max)
max = age;
sum = age;
}
ser = sum / kilk;
cout << "Average age of customers : " << to be << endl;
cout << "Min age of castomers : " << min << endl;
cout << "Max age of customers : " << max << endl;
}