Tasks: while loops, do while, nested loops

177 thoughts on “Tasks: while loops, do while, nested loops”

1. #include
   using namespace std;

   int main() {

   int _start = 0;
   int _end = 0;
   int _sumInputNumber = 0;

   cout <> _start;
   cout <> _end;

   for (int i = 0; i != _end+1; i ) {
   if (i % 2 != 0) {
   cout << i << " ";
   _sumInputNumber += i;
   }
   }
   cout << "\nAll the sum of whole odd integers from " << _start << " to " << _end << "are: " << _sumInputNumber;
   return 0;
   }

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2. —————- 3 ——————-
   #include
   using namespace std;

   int main() {

   int _inputNumber;
   string _toxer[100];
   string _hertakanTox;
   string _avelacvoxProblner;

   cout << "Enter the number tu build the tree, number will be a higth of tree" <> _inputNumber;

   for (int i = _inputNumber; i != 0; i–) { // toxeri blood
   for (int x = _inputNumber – i; x != 0; x–) {
   _avelacvoxProblner += ” “;
   }
   for (int j = 0; j != i*2-1; j ) {
   _hertakanTox + = “^”;
   }
   _toxer[i] = _avelacvoxProblner + _hertakanTox;
   _hertakanTox.clear();
   _avelacvoxProblner.clear();
   }
   for (int tpel = 0; nipple != _inputNumber + 1; nipple ++) {
   cout << _toxer[nipple] << endl;
   }
   return 0;
   }

   Reply

3. Si

   #include
   #include

   main()
   {
   int visota, i, j;
   printf(“Insert height: “);
   scanf_s(“%d”, &visota);

   for (i = 0; i <= visota; i ) // triangle height
   {
   for (j = 0; j < visota + i; j ) // list the number of characters in a string ( triangle width )
   {
   if (j <= visota – i) //
   {
   printf(" ");
   }
   else
   {
   printf("^");
   }

   }
   printf("\n");

   }

   }

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4. private void PrintTriangle()
   {
   int weigth = int.Parse(txbInput.Text);
   char symbol = char.Parse(txbSymbol.Text);

   for (int i = 0; i < weigth; i )
   {
   for (int j = 1; j <= i; j )
   {
   rtxbOutput.Text += symbol.ToString();
   }
   rtxbOutput.Text += symbol.ToString() + "\n";
   }
   }

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5. #include
   using namespace std;

   int main() {
   char c(‘^’);
   int a = 0;
   while (cin >> a && a > 0) {
   for (int d = 1; d <= a; d++) {
   int totalelok = (1 + (d – 1) * 2);
   string tempstr((1 + (a – 1) * 2), ' ');
   tempstr[tempstr.size() / 2] = c;
   for (int t = 1; t != totalelok; t += 2) {
   tempstr[tempstr.size() / 2 + ((t + 1) / 2)] = c;
   tempstr[tempstr.size() / 2 – ((t + 1) / 2)] = c;
   }
   cout << tempstr << endl;
   }
   }
   system("pause");
   return 0;
   }

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6. int main() {
   setlocale(0, “RU”);
   int h, b, x, Y;
   char sym = ‘^’;
   cout << "Введите высоту равнобедренного треугольника: " <> h;
   b = h + (h – 1);
   x = h;
   y = h;
   for (int i = 1; i <= h; i ) {
   for (int j = 1; j <= b; j ) {
   if (I) {
   cout << " ";
   }
   else {
   cout << sym;
   }
   }
   x -= 1;
   y += 1;
   cout << endl;
   }
   return 0;
   }

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7. I can’t figure out the triangle even with the code) what is in the triangle i and j?

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   1. I tried to chew 3 task
      The for loop looks like this:

      for ( definition of the control variable ;
      loop repetition condition ;
      changes in the control variable )

      The task is more difficult. Draw an isosceles
      triangle made of ^ symbols. Height selects
      user. For example: height = 5, on the screen

      #include
      using namespace std;

      int main()
      {

      int height = 0; // triangle height

      cout <> height;

      for (int i = 0; i < height; i ) //outer loop for lines
      { // start of outer loop
      // 2 nested loop – for spaces and for characters

      for (int j = 1; j < height – i; j )
      // i is taken from the outer loop
      // and j refers to this inner loop
      {
      cout << ' ';
      }
      //print spaces in a line

      for (int j = height – 2 * i; j <= height; j )
      // i is taken from the outer loop
      // and j already belongs to this inner loop

      //let's say height = 5 , then
      //in the zero line j=5, and i=0, so the sign will be displayed 1 times

      // and in the next line j=3 , i=1, (on the next outer loop)
      // so the sign is output 3 fold ,when j = alternately 3, 4, 5

      {
      cout << '^';
      }
      //sign printing

      cout << endl;
      } // end of outer loop
      return 0;
      }

      Reply

8. Third day of learning C++. But I already wrote a similar program in Python

   #include
   #include
   #include
   using namespace std;

   int main()
   {
   SetConsoleCP(1251);
   SetConsoleOutputCP(1251);

   int i;
   string a = ” “;
   string b = “^”;

   cout <> i;

   you e = 1;

   for (int n = 0; n < i; i–, e += 2) {

   for (int k = 0; k < i; k ) {
   cout << a;
   }

   for (int r = 0; r < e; r++) {
   cout << b;
   }
   cout << "\n";
   }

   return 0;
   }

   Reply